Name: Date:Solve the following quadratic equations:
Question 1: (t+1)^2+(2t+4)^2=(3t+1)^2 | Question 2: {\Large\frac{54w-21}{3w+4}}=4w+1 |
Question 3: (j+2)^2+(2j+3)^2=(2j+5)^2 | Question 4: {\Large\frac{56y-18}{5y+9}}=2y+1 |
Question 5: 27n^2-7n=-3n-5n^2+15 | Question 6: -{\Large\frac{88}{c-2}}+{\Large\frac{35}{c-1}}=12 |
Question 7: {\Large\frac{138k+37}{2k+9}}=9k+1 | Question 8: 57v^2-100v=-7v+3v^2-40 |
Question 9: -{\Large\frac{64}{z+2}}+{\Large\frac{143}{z+3}}=15 | Question 10: {\Large\frac{-140e-54}{4e-9}}=6e-1 |
Question 11: 24a^2-89a=-2a-4a^2-54 | Question 12: {\Large\frac{9}{g+1}}+{\Large\frac{13}{g+2}}=8 |
Question 13: -{\Large\frac{12}{d}}+{\Large\frac{1}{d+1}}=20 | Question 14: (u+4)^2+(3u+15)^2=(4u+13)^2 |
Question 15: 16s^2+54s=10s+4s^2+45 | Question 16: (p+6)^2+(p+7)^2=(p+8)^2 |
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Question 1: 4(t+1)(t-4)=0 \implies t=-1 , t=4 | Question 2: (3w-5)(4w-5)=0 \implies w={\Large\frac{5}{3}} , w={\Large\frac{5}{4}} |
Question 3: (j+2)(j-6)=0 \implies j=-2 , j=6 | Question 4: (5y-9)(2y-3)=0 \implies y={\Large\frac{9}{5}} , y={\Large\frac{3}{2}} |
Question 5: (8n+5)(4n-3)=0 \implies n=-{\Large\frac{5}{8}} , n={\Large\frac{3}{4}} | Question 6: (3c+2)(4c+3)=0 \implies c=-{\Large\frac{2}{3}} , c=-{\Large\frac{3}{4}} |
Question 7: (2k-7)(9k+4)=0 \implies k={\Large\frac{7}{2}} , k=-{\Large\frac{4}{9}} | Question 8: (6v-5)(9v-8)=0 \implies v={\Large\frac{5}{6}} , v={\Large\frac{8}{9}} |
Question 9: (5z+2)(3z-2)=0 \implies z=-{\Large\frac{2}{5}} , z={\Large\frac{2}{3}} | Question 10: (4e+9)(6e+7)=0 \implies e=-{\Large\frac{9}{4}} , e=-{\Large\frac{7}{6}} |
Question 11: (4a-9)(7a-6)=0 \implies a={\Large\frac{9}{4}} , a={\Large\frac{6}{7}} | Question 12: (2g+3)(4g-5)=0 \implies g=-{\Large\frac{3}{2}} , g={\Large\frac{5}{4}} |
Question 13: (4d+3)(5d+4)=0 \implies d=-{\Large\frac{3}{4}} , d=-{\Large\frac{4}{5}} | Question 14: 6(u+4)(u-3)=0 \implies u=-4 , u=3 |
Question 15: (2s+9)(6s-5)=0 \implies s=-{\Large\frac{9}{2}} , s={\Large\frac{5}{6}} | Question 16: (p+3)(p+7)=0 \implies p=-3 , p=-7 |