Name:                                    Date:

Solve the following quadratic equations:

Question 1: $(f+6)^2+(3f+21)^2=(4f+21)^2$	Question 2: $(s+1)^2+(s+2)^2=(s+3)^2$
Question 3: $-{\Large\frac{63}{t+1}}+{\Large\frac{130}{t+2}}=12$	Question 4: ${\Large\frac{132h-52}{6h+7}}=7h-1$
Question 5: ${\Large\frac{99y-39}{9y+4}}=5y-1$	Question 6: $-{\Large\frac{91}{w-2}}+{\Large\frac{18}{w-1}}=20$
Question 7: $(r-5)^2+(2r-11)^2=(2r-9)^2$	Question 8: $6e^2+49e=4e-8e^2+14$
Question 9: $3u^2-62u=-9u-39u^2-15$	Question 10: $-{\Large\frac{15}{j}}+{\Large\frac{45}{j+1}}=8$
Question 11: ${\Large\frac{8}{v+2}}+{\Large\frac{13}{v+3}}=10$	Question 12: $(m+2)^2+(2m+6)^2=(3m+4)^2$
Question 13: $26q^2-53q=-6q+6q^2-24$	Question 14: ${\Large\frac{138g+36}{4g+9}}=9g-1$
Question 15: ${\Large\frac{84k-42}{2k+7}}=6k-1$	Question 16: $42d^2-24d=-12d+10d^2+35$

Answers

Question 1: $6(f+6)(f-1)=0$ $\implies f=-6 , f=1$	Question 2: $(s-2)(s+2)=0$ $\implies s=2 , s=-2$
Question 3: $(3t-4)(4t-5)=0$ $\implies t={\Large\frac{4}{3}} , t={\Large\frac{5}{4}}$	Question 4: $(6h-5)(7h-9)=0$ $\implies h={\Large\frac{5}{6}} , h={\Large\frac{9}{7}}$
Question 5: $(9y-5)(5y-7)=0$ $\implies y={\Large\frac{5}{9}} , y={\Large\frac{7}{5}}$	Question 6: $(4w+5)(5w-3)=0$ $\implies w=-{\Large\frac{5}{4}} , w={\Large\frac{3}{5}}$
Question 7: $(r-5)(r-13)=0$ $\implies r=5 , r=13$	Question 8: $(2e+7)(7e-2)=0$ $\implies e=-{\Large\frac{7}{2}} , e={\Large\frac{2}{7}}$
Question 9: $(7u-3)(6u-5)=0$ $\implies u={\Large\frac{3}{7}} , u={\Large\frac{5}{6}}$	Question 10: $(2j-3)(4j-5)=0$ $\implies j={\Large\frac{3}{2}} , j={\Large\frac{5}{4}}$
Question 11: $(5v+2)(2v+5)=0$ $\implies v=-{\Large\frac{2}{5}} , v=-{\Large\frac{5}{2}}$	Question 12: $4(m+2)(m-3)=0$ $\implies m=-2 , m=3$
Question 13: $(4q-3)(5q-8)=0$ $\implies q={\Large\frac{3}{4}} , q={\Large\frac{8}{5}}$	Question 14: $(4g-9)(9g+5)=0$ $\implies g={\Large\frac{9}{4}} , g=-{\Large\frac{5}{9}}$
Question 15: $(2k-5)(6k-7)=0$ $\implies k={\Large\frac{5}{2}} , k={\Large\frac{7}{6}}$	Question 16: $(8d+7)(4d-5)=0$ $\implies d=-{\Large\frac{7}{8}} , d={\Large\frac{5}{4}}$