Name:                                    Date:

Solve the following quadratic equations:

Question 1: ${\Large\frac{15}{h}}-{\Large\frac{9}{h+1}}=8$	Question 2: $55m^2+17m=7m+7m^2+25$
Question 3: $(u+6)^2+(2u+14)^2=(3u+16)^2$	Question 4: $-{\Large\frac{14}{v+2}}+{\Large\frac{45}{v+3}}=6$
Question 5: ${\Large\frac{34j+17}{2j+5}}=5j+1$	Question 6: $39f^2-38f=-2f+7f^2-9$
Question 7: $-{\Large\frac{39}{c-2}}-{\Large\frac{8}{c-1}}=20$	Question 8: ${\Large\frac{18g+34}{3g-2}}=2g+1$
Question 9: $(e+2)^2+(e+3)^2=(e+4)^2$	Question 10: $19n^2-92n=-10n-44n^2-24$
Question 11: ${\Large\frac{7}{r+1}}+{\Large\frac{12}{r+2}}=10$	Question 12: $(q+4)^2+(3q+15)^2=(4q+13)^2$
Question 13: $7k^2+62k=5k-7k^2+27$	Question 14: $(z-5)^2+(2z-11)^2=(2z-9)^2$
Question 15: ${\Large\frac{20a+8}{9a+4}}=7a-1$	Question 16: ${\Large\frac{-76d-10}{7d-2}}=8d-1$

Answers

Question 1: $(4h-5)(2h+3)=0$ $\implies h={\Large\frac{5}{4}} , h=-{\Large\frac{3}{2}}$	Question 2: $(6m+5)(8m-5)=0$ $\implies m=-{\Large\frac{5}{6}} , m={\Large\frac{5}{8}}$
Question 3: $4(u+6)(u+1)=0$ $\implies u=-6 , u=-1$	Question 4: $(3v+4)(2v-3)=0$ $\implies v=-{\Large\frac{4}{3}} , v={\Large\frac{3}{2}}$
Question 5: $(2j-3)(5j+4)=0$ $\implies j={\Large\frac{3}{2}} , j=-{\Large\frac{4}{5}}$	Question 6: $(8f-3)(4f-3)=0$ $\implies f={\Large\frac{3}{8}} , f={\Large\frac{3}{4}}$
Question 7: $(5c+3)(4c-5)=0$ $\implies c=-{\Large\frac{3}{5}} , c={\Large\frac{5}{4}}$	Question 8: $(3g+4)(2g-9)=0$ $\implies g=-{\Large\frac{4}{3}} , g={\Large\frac{9}{2}}$
Question 9: $(e-1)(e+3)=0$ $\implies e=1 , e=-3$	Question 10: $(7n-6)(9n-4)=0$ $\implies n={\Large\frac{6}{7}} , n={\Large\frac{4}{9}}$
Question 11: $(2r+3)(5r-2)=0$ $\implies r=-{\Large\frac{3}{2}} , r={\Large\frac{2}{5}}$	Question 12: $6(q+4)(q-3)=0$ $\implies q=-4 , q=3$
Question 13: $(2k+9)(7k-3)=0$ $\implies k=-{\Large\frac{9}{2}} , k={\Large\frac{3}{7}}$	Question 14: $(z-5)(z-13)=0$ $\implies z=5 , z=13$
Question 15: $(9a-4)(7a+3)=0$ $\implies a={\Large\frac{4}{9}} , a=-{\Large\frac{3}{7}}$	Question 16: $(7d+4)(8d+3)=0$ $\implies d=-{\Large\frac{4}{7}} , d=-{\Large\frac{3}{8}}$