Name: Date:Write down the inverse function f^{-1}(x) , given:
| Question 1: f(x)={\Large\frac{7sin(x)}{4}} | Question 2: f(x)={\Large \frac {\sqrt{3x - 2}}{5}} |
| Question 3: f(x)=8 - 3sin(x) | Question 4: f(x)={\Large\frac{6}{x}} + 8 |
| Question 5: f(x)=7 + 5tan(x) | Question 6: f(x)={\Large\frac{x}{7}} + 2 |
| Question 7: f(x)={\Large\frac{2}{7}}(x - 7) + 9 | Question 8: f(x)={\Large \frac {9x^2 + 5}{2}} |
| Question 9: f(x)={\Large\frac{x}{5}} - 9 | Question 10: f(x)={\Large \frac {6x^2 - 5}{7}} |
| Question 11: f(x)=\sqrt{\Large\frac{7x + 4}{3}} | Question 12: f(x)={\Large \frac {\sqrt{6x + 5}}{7}} |
| Question 13: f(x)=tan(4x - 3) | Question 14: f(x)=sin(7x + 9) |
| Question 15: f(x)={\Large\frac{7}{x}} - 3 | Question 16: f(x)={\Large\frac{2tan(x)}{3}} |
| Question 17: f(x)={\Large\frac{8(x - 4)}{5}} + 3 | Question 18: f(x)=\sqrt{\Large\frac{6x - 5}{7}} |
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| Question 1: f^{-1}(x)=sin^{-1}{\Large(\frac{4x}{7})} | Question 2: f^{-1}(x)={\Large\frac{25x^2 + 2}{3}} |
| Question 3: f^{-1}(x)=sin^{-1}{\Large(\frac{8-x}{3})} | Question 4: f^{-1}(x)={\Large\frac{6}{x - 8}} |
| Question 5: f^{-1}(x)=tan^{-1}{\Large(\frac{x-7}{5})} | Question 6: f^{-1}(x)=7(x - 2) |
| Question 7: f^{-1}(x)={\Large\frac{7(x - 9)}{2}} + 7 | Question 8: f^{-1}(x)={\Large \sqrt{\frac{2x - 5}{9}}} |
| Question 9: f^{-1}(x)=5(x + 9) | Question 10: f^{-1}(x)={\Large \sqrt{\frac{7x + 5}{6}}} |
| Question 11: f^{-1}(x)={\Large\frac{3x^2 - 4}{7}} | Question 12: f^{-1}(x)={\Large\frac{49x^2 - 5}{6}} |
| Question 13: f^{-1}(x)={\Large\frac{tan^{-1}(x) + 3}{4}} | Question 14: f^{-1}(x)={\Large\frac{sin^{-1}(x) - 9}{7}} |
| Question 15: f^{-1}(x)={\Large\frac{7}{x + 3}} | Question 16: f^{-1}(x)=tan^{-1}{\Large(\frac{3x}{2})} |
| Question 17: f^{-1}(x)={\Large\frac{5(x - 3)}{8}} + 4 | Question 18: f^{-1}(x)={\Large\frac{7x^2 + 5}{6}} |