Name: Date:Write down the inverse function f^{-1}(x) , given:
| Question 1: f(x)=\sqrt{\Large\frac{7x + 5}{2}} | Question 2: f(x)={\Large\frac{9}{7}}(x + 4) + 6 |
| Question 3: f(x)={\Large \frac {8x^2 + 3}{5}} | Question 4: f(x)={\Large\frac{7tan(x)}{5}} |
| Question 5: f(x)=sin(8x - 7) | Question 6: f(x)={\Large \frac {\sqrt{3x - 5}}{4}} |
| Question 7: f(x)={\Large\frac{5(x - 8)}{2}} - 7 | Question 8: f(x)=2 + 7tan(x) |
| Question 9: f(x)=4 - 3sin(x) | Question 10: f(x)={\Large \frac {7x^2 - 2}{5}} |
| Question 11: f(x)={\Large\frac{x}{9}} + 2 | Question 12: f(x)=\sqrt{\Large\frac{5x - 7}{2}} |
| Question 13: f(x)=cos(4x + 6) | Question 14: f(x)={\Large\frac{6}{x}} + 2 |
| Question 15: f(x)={\Large\frac{3sin(x)}{5}} | Question 16: f(x)={\Large\frac{9}{x}} - 3 |
| Question 17: f(x)={\Large \frac {\sqrt{5x + 3}}{4}} | Question 18: f(x)={\Large\frac{x}{3}} - 8 |
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| Question 1: f^{-1}(x)={\Large\frac{2x^2 - 5}{7}} | Question 2: f^{-1}(x)={\Large\frac{7(x - 6)}{9}} - 4 |
| Question 3: f^{-1}(x)={\Large \sqrt{\frac{5x - 3}{8}}} | Question 4: f^{-1}(x)=tan^{-1}{\Large(\frac{5x}{7})} |
| Question 5: f^{-1}(x)={\Large\frac{sin^{-1}(x) + 7}{8}} | Question 6: f^{-1}(x)={\Large\frac{16x^2 + 5}{3}} |
| Question 7: f^{-1}(x)={\Large\frac{2(x + 7)}{5}} + 8 | Question 8: f^{-1}(x)=tan^{-1}{\Large(\frac{x-2}{7})} |
| Question 9: f^{-1}(x)=sin^{-1}{\Large(\frac{4-x}{3})} | Question 10: f^{-1}(x)={\Large \sqrt{\frac{5x + 2}{7}}} |
| Question 11: f^{-1}(x)=9(x - 2) | Question 12: f^{-1}(x)={\Large\frac{2x^2 + 7}{5}} |
| Question 13: f^{-1}(x)={\Large\frac{cos^{-1}(x) - 6}{4}} | Question 14: f^{-1}(x)={\Large\frac{6}{x - 2}} |
| Question 15: f^{-1}(x)=sin^{-1}{\Large(\frac{5x}{3})} | Question 16: f^{-1}(x)={\Large\frac{9}{x + 3}} |
| Question 17: f^{-1}(x)={\Large\frac{16x^2 - 3}{5}} | Question 18: f^{-1}(x)=3(x + 8) |