Name: Date:Write down the inverse function f^{-1}(x) , given:
| Question 1: f(x)=cos(4x - 3) | Question 2: f(x)={\Large \frac {\sqrt{9x + 5}}{2}} |
| Question 3: f(x)={\Large\frac{5sin(x)}{3}} | Question 4: f(x)={\Large\frac{8cos(x)}{3}} |
| Question 5: f(x)=2 - 3sin(x) | Question 6: f(x)=\sqrt{\Large\frac{2x + 5}{7}} |
| Question 7: f(x)=\sqrt{\Large\frac{9x - 7}{4}} | Question 8: f(x)={\Large\frac{5}{x}} + 9 |
| Question 9: f(x)=7 + 3cos(x) | Question 10: f(x)={\Large\frac{x}{3}} - 4 |
| Question 11: f(x)={\Large\frac{7}{3}}(x - 2) + 8 | Question 12: f(x)={\Large\frac{x}{2}} + 9 |
| Question 13: f(x)={\Large\frac{7}{x}} - 8 | Question 14: f(x)={\Large \frac {3x^2 + 7}{5}} |
| Question 15: f(x)={\Large\frac{4(x + 4)}{5}} + 3 | Question 16: f(x)={\Large \frac {\sqrt{4x - 5}}{3}} |
| Question 17: f(x)=tan(2x + 8) | Question 18: f(x)={\Large \frac {3x^2 - 7}{5}} |
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| Question 1: f^{-1}(x)={\Large\frac{cos^{-1}(x) + 3}{4}} | Question 2: f^{-1}(x)={\Large\frac{4x^2 - 5}{9}} |
| Question 3: f^{-1}(x)=sin^{-1}{\Large(\frac{3x}{5})} | Question 4: f^{-1}(x)=cos^{-1}{\Large(\frac{3x}{8})} |
| Question 5: f^{-1}(x)=sin^{-1}{\Large(\frac{2-x}{3})} | Question 6: f^{-1}(x)={\Large\frac{7x^2 - 5}{2}} |
| Question 7: f^{-1}(x)={\Large\frac{4x^2 + 7}{9}} | Question 8: f^{-1}(x)={\Large\frac{5}{x - 9}} |
| Question 9: f^{-1}(x)=cos^{-1}{\Large(\frac{x-7}{3})} | Question 10: f^{-1}(x)=3(x + 4) |
| Question 11: f^{-1}(x)={\Large\frac{3(x - 8)}{7}} + 2 | Question 12: f^{-1}(x)=2(x - 9) |
| Question 13: f^{-1}(x)={\Large\frac{7}{x + 8}} | Question 14: f^{-1}(x)={\Large \sqrt{\frac{5x - 7}{3}}} |
| Question 15: f^{-1}(x)={\Large\frac{5(x - 3)}{4}} - 4 | Question 16: f^{-1}(x)={\Large\frac{9x^2 + 5}{4}} |
| Question 17: f^{-1}(x)={\Large\frac{tan^{-1}(x) - 8}{2}} | Question 18: f^{-1}(x)={\Large \sqrt{\frac{5x + 7}{3}}} |