Name: Date:Write down the inverse function f^{-1}(x) , given:
| Question 1: f(x)={\Large\frac{2}{x}} - 7 | Question 2: f(x)=6 - 5sin(x) |
| Question 3: f(x)=\sqrt{\Large\frac{3x + 5}{7}} | Question 4: f(x)=tan(7x + 8) |
| Question 5: f(x)={\Large\frac{6}{x}} + 9 | Question 6: f(x)={\Large \frac {\sqrt{7x + 4}}{5}} |
| Question 7: f(x)=cos(4x - 3) | Question 8: f(x)=3 + 5tan(x) |
| Question 9: f(x)={\Large\frac{7cos(x)}{4}} | Question 10: f(x)={\Large\frac{x}{7}} + 6 |
| Question 11: f(x)={\Large\frac{x}{2}} - 9 | Question 12: f(x)={\Large\frac{9}{4}}(x + 7) - 8 |
| Question 13: f(x)={\Large\frac{6(x - 4)}{5}} + 3 | Question 14: f(x)={\Large \frac {2x^2 + 5}{3}} |
| Question 15: f(x)={\Large \frac {5x^2 - 4}{7}} | Question 16: f(x)=\sqrt{\Large\frac{9x - 2}{5}} |
| Question 17: f(x)={\Large\frac{6sin(x)}{5}} | Question 18: f(x)={\Large \frac {\sqrt{3x - 7}}{5}} |
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| Question 1: f^{-1}(x)={\Large\frac{2}{x + 7}} | Question 2: f^{-1}(x)=sin^{-1}{\Large(\frac{6-x}{5})} |
| Question 3: f^{-1}(x)={\Large\frac{7x^2 - 5}{3}} | Question 4: f^{-1}(x)={\Large\frac{tan^{-1}(x) - 8}{7}} |
| Question 5: f^{-1}(x)={\Large\frac{6}{x - 9}} | Question 6: f^{-1}(x)={\Large\frac{25x^2 - 4}{7}} |
| Question 7: f^{-1}(x)={\Large\frac{cos^{-1}(x) + 3}{4}} | Question 8: f^{-1}(x)=tan^{-1}{\Large(\frac{x-3}{5})} |
| Question 9: f^{-1}(x)=cos^{-1}{\Large(\frac{4x}{7})} | Question 10: f^{-1}(x)=7(x - 6) |
| Question 11: f^{-1}(x)=2(x + 9) | Question 12: f^{-1}(x)={\Large\frac{4(x + 8)}{9}} - 7 |
| Question 13: f^{-1}(x)={\Large\frac{5(x - 3)}{6}} + 4 | Question 14: f^{-1}(x)={\Large \sqrt{\frac{3x - 5}{2}}} |
| Question 15: f^{-1}(x)={\Large \sqrt{\frac{7x + 4}{5}}} | Question 16: f^{-1}(x)={\Large\frac{5x^2 + 2}{9}} |
| Question 17: f^{-1}(x)=sin^{-1}{\Large(\frac{5x}{6})} | Question 18: f^{-1}(x)={\Large\frac{25x^2 + 7}{3}} |