Name: Date:Write down the inverse function f^{-1}(x) , given:
| Question 1: f(x)={\Large \frac {5x^2 - 7}{3}} | Question 2: f(x)={\Large\frac{9sin(x)}{4}} |
| Question 3: f(x)={\Large\frac{7cos(x)}{3}} | Question 4: f(x)={\Large\frac{6}{x}} - 7 |
| Question 5: f(x)={\Large\frac{x}{9}} + 8 | Question 6: f(x)={\Large\frac{4}{x}} + 2 |
| Question 7: f(x)={\Large\frac{x}{7}} - 3 | Question 8: f(x)=\sqrt{\Large\frac{8x + 5}{3}} |
| Question 9: f(x)={\Large \frac {3x^2 + 2}{7}} | Question 10: f(x)=\sqrt{\Large\frac{4x - 7}{5}} |
| Question 11: f(x)=8 + 5sin(x) | Question 12: f(x)=tan(9x - 4) |
| Question 13: f(x)={\Large \frac {\sqrt{2x + 7}}{5}} | Question 14: f(x)=cos(5x + 6) |
| Question 15: f(x)={\Large\frac{4(x - 9)}{5}} - 4 | Question 16: f(x)=6 - 5cos(x) |
| Question 17: f(x)={\Large \frac {\sqrt{3x - 7}}{5}} | Question 18: f(x)={\Large\frac{9}{2}}(x + 5) + 6 |
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| Question 1: f^{-1}(x)={\Large \sqrt{\frac{3x + 7}{5}}} | Question 2: f^{-1}(x)=sin^{-1}{\Large(\frac{4x}{9})} |
| Question 3: f^{-1}(x)=cos^{-1}{\Large(\frac{3x}{7})} | Question 4: f^{-1}(x)={\Large\frac{6}{x + 7}} |
| Question 5: f^{-1}(x)=9(x - 8) | Question 6: f^{-1}(x)={\Large\frac{4}{x - 2}} |
| Question 7: f^{-1}(x)=7(x + 3) | Question 8: f^{-1}(x)={\Large\frac{3x^2 - 5}{8}} |
| Question 9: f^{-1}(x)={\Large \sqrt{\frac{7x - 2}{3}}} | Question 10: f^{-1}(x)={\Large\frac{5x^2 + 7}{4}} |
| Question 11: f^{-1}(x)=sin^{-1}{\Large(\frac{x-8}{5})} | Question 12: f^{-1}(x)={\Large\frac{tan^{-1}(x) + 4}{9}} |
| Question 13: f^{-1}(x)={\Large\frac{25x^2 - 7}{2}} | Question 14: f^{-1}(x)={\Large\frac{cos^{-1}(x) - 6}{5}} |
| Question 15: f^{-1}(x)={\Large\frac{5(x + 4)}{4}} + 9 | Question 16: f^{-1}(x)=cos^{-1}{\Large(\frac{6-x}{5})} |
| Question 17: f^{-1}(x)={\Large\frac{25x^2 + 7}{3}} | Question 18: f^{-1}(x)={\Large\frac{2(x - 6)}{9}} - 5 |