Name: Date:Write down the inverse function f^{-1}(x) , given:
| Question 1: f(x)={\Large\frac{x}{3}} - 5 | Question 2: f(x)={\Large \frac {\sqrt{5x + 3}}{7}} |
| Question 3: f(x)=\sqrt{\Large\frac{6x - 7}{5}} | Question 4: f(x)={\Large\frac{3(x - 7)}{4}} - 9 |
| Question 5: f(x)={\Large \frac {\sqrt{4x - 7}}{5}} | Question 6: f(x)=4 - 5cos(x) |
| Question 7: f(x)=sin(2x + 8) | Question 8: f(x)=8 + 3sin(x) |
| Question 9: f(x)={\Large \frac {7x^2 - 3}{4}} | Question 10: f(x)={\Large \frac {9x^2 + 5}{2}} |
| Question 11: f(x)=\sqrt{\Large\frac{9x + 4}{7}} | Question 12: f(x)={\Large\frac{8sin(x)}{3}} |
| Question 13: f(x)={\Large\frac{2}{x}} - 5 | Question 14: f(x)={\Large\frac{8}{3}}(x + 2) + 8 |
| Question 15: f(x)={\Large\frac{5cos(x)}{7}} | Question 16: f(x)={\Large\frac{x}{8}} + 7 |
| Question 17: f(x)=cos(7x - 9) | Question 18: f(x)={\Large\frac{9}{x}} + 3 |
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| Question 1: f^{-1}(x)=3(x + 5) | Question 2: f^{-1}(x)={\Large\frac{49x^2 - 3}{5}} |
| Question 3: f^{-1}(x)={\Large\frac{5x^2 + 7}{6}} | Question 4: f^{-1}(x)={\Large\frac{4(x + 9)}{3}} + 7 |
| Question 5: f^{-1}(x)={\Large\frac{25x^2 + 7}{4}} | Question 6: f^{-1}(x)=cos^{-1}{\Large(\frac{4-x}{5})} |
| Question 7: f^{-1}(x)={\Large\frac{sin^{-1}(x) - 8}{2}} | Question 8: f^{-1}(x)=sin^{-1}{\Large(\frac{x-8}{3})} |
| Question 9: f^{-1}(x)={\Large \sqrt{\frac{4x + 3}{7}}} | Question 10: f^{-1}(x)={\Large \sqrt{\frac{2x - 5}{9}}} |
| Question 11: f^{-1}(x)={\Large\frac{7x^2 - 4}{9}} | Question 12: f^{-1}(x)=sin^{-1}{\Large(\frac{3x}{8})} |
| Question 13: f^{-1}(x)={\Large\frac{2}{x + 5}} | Question 14: f^{-1}(x)={\Large\frac{3(x - 8)}{8}} - 2 |
| Question 15: f^{-1}(x)=cos^{-1}{\Large(\frac{7x}{5})} | Question 16: f^{-1}(x)=8(x - 7) |
| Question 17: f^{-1}(x)={\Large\frac{cos^{-1}(x) + 9}{7}} | Question 18: f^{-1}(x)={\Large\frac{9}{x - 3}} |