Name: Date:Write down the inverse function f^{-1}(x) , given:
| Question 1: f(x)=5 - 3cos(x) | Question 2: f(x)={\Large\frac{6sin(x)}{5}} |
| Question 3: f(x)=\sqrt{\Large\frac{7x - 3}{5}} | Question 4: f(x)={\Large\frac{2}{x}} + 5 |
| Question 5: f(x)={\Large\frac{4(x - 9)}{7}} - 2 | Question 6: f(x)={\Large \frac {\sqrt{2x + 3}}{7}} |
| Question 7: f(x)=cos(9x - 2) | Question 8: f(x)={\Large\frac{x}{8}} - 4 |
| Question 9: f(x)=7 + 3sin(x) | Question 10: f(x)={\Large\frac{7tan(x)}{5}} |
| Question 11: f(x)={\Large\frac{x}{7}} + 2 | Question 12: f(x)={\Large\frac{4}{5}}(x - 6) - 5 |
| Question 13: f(x)={\Large \frac {\sqrt{5x - 7}}{3}} | Question 14: f(x)=tan(6x + 5) |
| Question 15: f(x)={\Large\frac{3}{x}} - 6 | Question 16: f(x)={\Large \frac {8x^2 + 5}{7}} |
| Question 17: f(x)=\sqrt{\Large\frac{2x + 3}{7}} | Question 18: f(x)={\Large \frac {2x^2 - 5}{3}} |
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| Question 1: f^{-1}(x)=cos^{-1}{\Large(\frac{5-x}{3})} | Question 2: f^{-1}(x)=sin^{-1}{\Large(\frac{5x}{6})} |
| Question 3: f^{-1}(x)={\Large\frac{5x^2 + 3}{7}} | Question 4: f^{-1}(x)={\Large\frac{2}{x - 5}} |
| Question 5: f^{-1}(x)={\Large\frac{7(x + 2)}{4}} + 9 | Question 6: f^{-1}(x)={\Large\frac{49x^2 - 3}{2}} |
| Question 7: f^{-1}(x)={\Large\frac{cos^{-1}(x) + 2}{9}} | Question 8: f^{-1}(x)=8(x + 4) |
| Question 9: f^{-1}(x)=sin^{-1}{\Large(\frac{x-7}{3})} | Question 10: f^{-1}(x)=tan^{-1}{\Large(\frac{5x}{7})} |
| Question 11: f^{-1}(x)=7(x - 2) | Question 12: f^{-1}(x)={\Large\frac{5(x + 5)}{4}} + 6 |
| Question 13: f^{-1}(x)={\Large\frac{9x^2 + 7}{5}} | Question 14: f^{-1}(x)={\Large\frac{tan^{-1}(x) - 5}{6}} |
| Question 15: f^{-1}(x)={\Large\frac{3}{x + 6}} | Question 16: f^{-1}(x)={\Large \sqrt{\frac{7x - 5}{8}}} |
| Question 17: f^{-1}(x)={\Large\frac{7x^2 - 3}{2}} | Question 18: f^{-1}(x)={\Large \sqrt{\frac{3x + 5}{2}}} |