Name: Date:Write down the inverse function f^{-1}(x) , given:
| Question 1: f(x)={\Large \frac {\sqrt{4x - 7}}{3}} | Question 2: f(x)={\Large\frac{5}{x}} + 7 |
| Question 3: f(x)={\Large\frac{2}{7}}(x + 3) + 6 | Question 4: f(x)={\Large \frac {7x^2 + 4}{3}} |
| Question 5: f(x)=5 + 2tan(x) | Question 6: f(x)=sin(3x + 6) |
| Question 7: f(x)={\Large\frac{6}{x}} - 3 | Question 8: f(x)={\Large\frac{x}{5}} + 8 |
| Question 9: f(x)={\Large\frac{6(x + 7)}{7}} + 9 | Question 10: f(x)=cos(7x - 9) |
| Question 11: f(x)={\Large \frac {\sqrt{4x + 3}}{7}} | Question 12: f(x)={\Large\frac{3tan(x)}{7}} |
| Question 13: f(x)={\Large \frac {6x^2 - 7}{5}} | Question 14: f(x)={\Large\frac{x}{3}} - 2 |
| Question 15: f(x)={\Large\frac{3sin(x)}{7}} | Question 16: f(x)=\sqrt{\Large\frac{2x - 7}{3}} |
| Question 17: f(x)=\sqrt{\Large\frac{2x + 7}{5}} | Question 18: f(x)=5 - 2cos(x) |
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| Question 1: f^{-1}(x)={\Large\frac{9x^2 + 7}{4}} | Question 2: f^{-1}(x)={\Large\frac{5}{x - 7}} |
| Question 3: f^{-1}(x)={\Large\frac{7(x - 6)}{2}} - 3 | Question 4: f^{-1}(x)={\Large \sqrt{\frac{3x - 4}{7}}} |
| Question 5: f^{-1}(x)=tan^{-1}{\Large(\frac{x-5}{2})} | Question 6: f^{-1}(x)={\Large\frac{sin^{-1}(x) - 6}{3}} |
| Question 7: f^{-1}(x)={\Large\frac{6}{x + 3}} | Question 8: f^{-1}(x)=5(x - 8) |
| Question 9: f^{-1}(x)={\Large\frac{7(x - 9)}{6}} - 7 | Question 10: f^{-1}(x)={\Large\frac{cos^{-1}(x) + 9}{7}} |
| Question 11: f^{-1}(x)={\Large\frac{49x^2 - 3}{4}} | Question 12: f^{-1}(x)=tan^{-1}{\Large(\frac{7x}{3})} |
| Question 13: f^{-1}(x)={\Large \sqrt{\frac{5x + 7}{6}}} | Question 14: f^{-1}(x)=3(x + 2) |
| Question 15: f^{-1}(x)=sin^{-1}{\Large(\frac{7x}{3})} | Question 16: f^{-1}(x)={\Large\frac{3x^2 + 7}{2}} |
| Question 17: f^{-1}(x)={\Large\frac{5x^2 - 7}{2}} | Question 18: f^{-1}(x)=cos^{-1}{\Large(\frac{5-x}{2})} |