The graph above shows the velocity of a car over 30 seconds.Name: Date:

1) What was the velocity at time t=24 seconds (to the nearest whole number)?

2) How many seconds did it take to reach a velocity of 48m/s (to the nearest whole number)?

3) Work out the average gradient between t=0 and t=30 seconds (correct to 1 d.p.)

4) Estimate the instantaneous rate of change at 12 seconds (correct to 1 d.p.)

5) Interpret your result:

- What does the instantaneous rate of change represent?

- Compare the instantaneous rate of change at 12 seconds with the average gradient

- What is happening over time?

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2) 8 seconds

3) average gradient = 1.2

4) gradient at t=12 is 1.1

5) The gradient represents the acceleration of the car. The gradient at 12s is less than the average gradient over 30 seconds. Over time the car is accelerating at a decreasing rate.

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1) 63m/s2) 8 seconds

3) average gradient = 1.2

4) gradient at t=12 is 1.1

5) The gradient represents the acceleration of the car. The gradient at 12s is less than the average gradient over 30 seconds. Over time the car is accelerating at a decreasing rate.

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