The graph above shows the velocity of a car over 30 seconds.Name: Date:

1) What was the velocity at time t=12 seconds (to the nearest whole number)?

2) How many seconds did it take to reach a velocity of 13m/s (to the nearest whole number)?

3) Work out the average gradient between t=0 and t=30 seconds (correct to 1 d.p.)

4) Estimate the instantaneous rate of change at 16 seconds (correct to 1 d.p.)

5) Interpret your result:

- What does the instantaneous rate of change represent?

- Compare the instantaneous rate of change at 16 seconds with the average gradient

- What is happening over time?

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2) 20 seconds

3) average gradient = 1.3

4) gradient at t=16 is 0.9

5) The gradient represents the acceleration of the car. The gradient at 16s is less than the average gradient over 30 seconds. Over time the car is accelerating at an increasing rate.

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1) 5m/s2) 20 seconds

3) average gradient = 1.3

4) gradient at t=16 is 0.9

5) The gradient represents the acceleration of the car. The gradient at 16s is less than the average gradient over 30 seconds. Over time the car is accelerating at an increasing rate.

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