The graph above shows the distance travelled by a car over 30 seconds.Name: Date:

1) What was the distance at time t=24 seconds (to the nearest whole number)?

2) How many seconds did it take to reach a distance of 48m (to the nearest whole number)?

3) Work out the average gradient between t=0 and t=30 seconds (correct to 1 d.p.)

4) Estimate the gradient at 8 seconds (correct to 1 d.p.)

5) Interpret your result:

- What does this gradient represent?

- Compare the gradient at 8 seconds with the average gradient

- What is happening over time?

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2) 20 seconds

3) average gradient = 1.2

4) gradient at t=8 is 1.4

5) The gradient represents the velocity of the car. The gradient at 8s is greater than the average gradient over 30 seconds. Over time the car is being driven at decreasing velocity.

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1) 50m2) 20 seconds

3) average gradient = 1.2

4) gradient at t=8 is 1.4

5) The gradient represents the velocity of the car. The gradient at 8s is greater than the average gradient over 30 seconds. Over time the car is being driven at decreasing velocity.

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